/* This function was copied from a freely-available version at 

http://javascript.internet.com/forms/check-email.html

Changes:  Sandeep V. Tamhankar (stamhankar@hotmail.com)

*/

/* 1.1.2: Fixed a bug where trailing . in e-mail address was passing
            (the bug is actually in the weak regexp engine of the browser; I
            simplified the regexps to make it work).
   1.1.1: Removed restriction that countries must be preceded by a domain,
            so abc@host.uk is now legal.  However, there's still the 
            restriction that an address must end in a two or three letter
            word.
     1.1: Rewrote most of the function to conform more closely to RFC 822.
     1.0: Original  */

<!-- This script and many more are available free online at -->
<!-- The JavaScript Source!! http://javascript.internet.com -->

<!-- Begin
function emailValidate (emailStr) {
/* The following pattern is used to check if the entered e-mail address
   fits the user@domain format.  It also is used to separate the username
   from the domain. */
var emailPat=/^(.+)@(.+)$/
/* This pattern should match strings with only blank characters. */
var blankPat = /^\s*$/
/* The following string represents the pattern for matching all special
   characters.  We don't want to allow special characters in the address. 
   These characters include ( ) < > @ , ; : \ " . [ ]    */
var specialChars="\\(\\)<>@,;:\\\\\\\"\\.\\[\\]"
/* The following string represents the range of characters allowed in a 
   username or domainname.  It really states which chars aren't allowed. */
var validChars="\[^\\s" + specialChars + "\]"
/* The following pattern applies if the "user" is a quoted string (in
   which case, there are no rules about which characters are allowed
   and which aren't; anything goes).  E.g. "jiminy cricket"@disney.com
   is a legal e-mail address. */
var quotedUser="(\"[^\"]*\")"
/* The following pattern applies for domains that are IP addresses,
   rather than symbolic names.  E.g. joe@[123.124.233.4] is a legal
   e-mail address. NOTE: The square brackets are required. */
var ipDomainPat=/^\[(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})\]$/
/* The following string represents an atom (basically a series of
   non-special characters.) */
var atom=validChars + '+'
/* The following string represents one word in the typical username.
   For example, in john.doe@somewhere.com, john and doe are words.
   Basically, a word is either an atom or quoted string. */
var word="(" + atom + "|" + quotedUser + ")"
// The following pattern describes the structure of the user
var userPat=new RegExp("^" + word + "(\\." + word + ")*$")
/* The following pattern describes the structure of a normal symbolic
   domain, as opposed to ipDomainPat, shown above. */
var domainPat=new RegExp("^" + atom + "(\\." + atom +")*$")


/* Finally, let's start trying to figure out if the supplied address is
   valid. */

/* Begin with the coarse pattern to simply break up user@domain into
   different pieces that are easy to analyze. */
var matchArray=emailStr.match(emailPat)
if (matchArray==null) {
  /* Too many/few @'s or something; basically, this address doesn't
     even fit the general mould of a valid e-mail address. */
	if (emailStr.match(blankPat) != null) {
		return "Email address is blank"
	}
	return 'Check format for yourname@yourprovider(".com" ".net" , etc)'
}
var user=matchArray[1]
var domain=matchArray[2]

// See if "user" is valid 
if (user.match(userPat)==null) {
    // user is not valid
    return "The username doesn't seem to be valid"
}

/* if the e-mail address is at an IP address (as opposed to a symbolic
   host name) make sure the IP address is valid. */
var IPArray=domain.match(ipDomainPat)
if (IPArray!=null) {
    // this is an IP address
	  for (var i=1;i<=4;i++) {
	    if (IPArray[i]>255) {
	        return "Destination IP address is invalid!"
	    }
    }
    return true
}

// Domain is symbolic name
var domainArray=domain.match(domainPat)
if (domainArray==null) {
	return "The domain name doesn't seem to be valid"
}

/* domain name seems valid, but now make sure that it ends in a
   three-letter word (like com, edu, gov) or a two-letter word,
   representing country (uk, nl), and that there's a hostname preceding 
   the domain or country. */

/* Now we need to break up the domain to get a count of how many atoms
   it consists of. */
var atomPat=new RegExp(atom,"g")
var domArr=domain.match(atomPat)
var len=domArr.length
if (domArr[domArr.length-1].length<2 || 
    domArr[domArr.length-1].length>3) {
   // the address must end in a two letter or three letter word.
   return "The address must end in a three-letter domain, or two letter country"
}

// Make sure there's a host name preceding the domain.
if (len<2) {
   return "This address is missing a hostname"
}

// If we've gotten this far, everything's valid!
return true;
}


function validDate(year, month, day) {
	if (isNaN(parseInt(year)) || isNaN(parseInt(month)) || isNaN(parseInt(day))) {
		return false
	}
	with (new Date(year, month - 1, day)) {
		return getMonth() == (month - 1) 
				&& getDate() == day;
	}	
}

/*
Ultimate Age calculator script- By JavaScript Kit (http://www.javascriptkit.com)
Over 200+ free scripts here!
Credit must stay intact for use

Modified by Larry Edelstein to return a numeric value, instead of writing it to the document, 
and without the unit string.
*/

var one_day=1000*60*60*24
var one_month=1000*60*60*24*30
var one_year=1000*60*60*24*30*12

function displayAge(yr, mon, day, unit, decimal, round, fromStartOfYear) {
	fromDate = new Date()
	if (fromStartOfYear != undefined) {
		fromDate = new Date(fromDate.getFullYear(), 0, 1, 0, 0, 0, 0)
	}
	var pastdate=new Date(yr, mon-1, day)

	var countunit = unit
	var decimals = decimal
	var rounding = round

	finalunit = (countunit == "days")? one_day : (countunit == "months")? one_month : one_year
	decimals = (decimals <= 0) ? 1 : decimals * 10

	if (unit != "years") {
		if (rounding == "rounddown")
			return Math.floor((fromDate.getTime() - pastdate.getTime()) / (finalunit) * decimals) / decimals
		else
			return Math.ceil((fromDate.getTime() - pastdate.getTime()) / (finalunit) * decimals) / decimals
	} 
	yearspast = fromDate.getFullYear() - yr - 1
	tail = (fromDate.getMonth() > mon-1 || fromDate.getMonth() == mon - 1 && fromDate.getDate() >= day) ? 1 : 0
	pastdate.setFullYear(fromDate.getFullYear())
	pastdate2 = new Date(fromDate.getFullYear() - 1, mon - 1, day)
	tail = (tail == 1) 
		? tail + Math.floor((fromDate.getTime() - pastdate.getTime()) / (finalunit) * decimals) / decimals 
		: Math.floor((fromDate.getTime() - pastdate2.getTime()) / (finalunit) * decimals) / decimals
	return yearspast + tail
}

//Sample usage
//displayage (year, month, day, unit, decimals, rounding)
//Unit can be "years", "months", or "days"
//Decimals specifies demical places to round to (ie: 2)
//Rounding can be "roundup" or "rounddown"

//displayage(1997, 11, 24, "years", 0, "rounddown")